1 条题解

  • 0
    @ 2024-1-29 16:15:14

    C++ :

    #include<bits/stdc++.h>
    using namespace std;
    
    int A[105], n, m;
    
    int check(int mid) {
        int k = mid, q = 1;
        for (int i = 1; i <= n; i++) {
            if (k - A[i] >= 0) {
                k -= A[i];
            } else {
                k = mid - A[i];
                if (k < 0)
                    return 0;
                q++;
            }
        }
        if (q > m)
            return 0;
        else
            return 1;
    }
    
    int main() {
        scanf("%d %d", &n, &m);
        int l = 1, r = 0;
        for (int i = 1; i <= n; i++) {
            scanf("%d", &A[i]);
            r += A[i];
        }
        while (l <= r) {
            int mid = (l + r) / 2;
            if (check(mid))
                r = mid - 1;
            else
                l = mid + 1;
        }
        printf("%d", l);
        return 0;
    }
    
    • 1

    信息

    ID
    536
    时间
    1000ms
    内存
    128MiB
    难度
    (无)
    标签
    (无)
    递交数
    0
    已通过
    0
    上传者